• expr@piefed.social
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    2 months ago

    I assume it’s not just about the gravity, but also the much larger radius of the planet would mean much larger distance from the surface, and thus much more fuel needed.

    • potatopotato@sh.itjust.works
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      2 months ago

      That’s not how…what???

      F = G * (m1 * m2) / r^2

      Note that radius is both squared and the dividing term. More distance = less gravity

        • Lojcs@piefed.social
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          2 months ago

          Wikipedia says energy = GMm/r.

          if g=GM/r² then energy = mgr, proportional to r given g is constant.

          apologies

          My previous comment was wrong, I derivated while integrating.

      • expr@piefed.social
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        2 months ago

        I stated an assumption and was contributing to the conversation. Even if that assumption is incorrect, there’s no need to be a dick about it.

        It seems like a larger atmosphere would result in a longer duration exposed to atmospheric drag, thus requiring more fuel to overcome it.

    • turdas@suppo.fi
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      2 months ago

      That’s, uh, not really how that works. A taller atmosphere would mean you have to go through more of it, but unless it’s not a terrestrial then the atmosphere won’t be that much taller.

      If it is a non-terrestrial planet, it’s unlikely anyone would be building rockets on there to begin with.

      • Pyr@lemmy.ca
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        2 months ago

        If it has a higher gravity would the atmosphere technically be lower since it will squish up closer to the planet?