fossilesque@mander.xyzM to Science Memes@mander.xyzEnglish · 2 months agoSo muchmander.xyzexternal-linkmessage-square21fedilinkarrow-up1340arrow-down15
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minus-squareemergencyfood@sh.itjust.workslinkfedilinkEnglisharrow-up2arrow-down2·2 months agoNot a mathematician, but I’m pretty sure this isn’t necessarily true. What if L is -1 and f(x) = x^2? Also I think your function has to be continuous.
minus-squaredavidagain@lemmy.worldlinkfedilinkEnglisharrow-up3·edit-22 months agoYou’re right on all three counts. It’s not always true, f(x0) has to be L, and the function has to be continuous.
Not a mathematician, but I’m pretty sure this isn’t necessarily true. What if L is -1 and f(x) = x^2? Also I think your function has to be continuous.
You’re right on all three counts. It’s not always true, f(x0) has to be L, and the function has to be continuous.